Physics
WAEC 1993
Calculate the current, I in the diagram shown above.
(Neglect the internal resistance of the cell)
-
A.
4.0A
-
B.
2.0A
-
C.
1.0A
-
D.
O.5A
-
E.
0.1A.
Correct Answer: Option C
Explanation
R = 2 + 2 = 4 Ω; 1/R = ¼ + ¼ = 2/4; R = 2Ω
∴ I = V/R = 2/2 = 1A
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