Physics
WAEC 1993
A man stands in front of a tall wall and produces a sound. If he receives the echo of the sound two seconds later, calculate his distance from the wall. (The speed of sound in air is 330ms
-1)
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A.
600m
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B.
400m
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C.
330m
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D.
328m
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E.
165m
Correct Answer: Option C
Explanation
x = vt/2 = \(\frac {330 \times 2} {2}\) = 660/2 = 330m
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