Physics
WAEC 1992
Calculate the time in which 4.8 kJ of energy would be expended when an electric heater of resistance 1.8 x 10
3Ω is used on a 240 V mains supply. (Neglect heat losses to the surrounding).
-
A.
150.0s
-
B.
90.0s
-
C.
36.0s
-
D.
20.0s
-
E.
2.7s.
Correct Answer: Option A
Explanation
E = V
2t/R
t =
ER/V2
=
4800 x 1.8 x 103/240 x 240
= 150s
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