Physics
WAEC 1992
Calculate the length of a constantan wire of cross- sectional area 4 π x 10
-8m
2 and resistivity 1.1 x 10
-6 Ω m required to construct a standard resistor of resistance 21 Ω. [Take π = 22/7]
-
A.
0.42m
-
B.
2.40 m
-
C.
6.25 m
-
D.
183.75 m
-
E.
590.00 m
Correct Answer: Option B
Explanation
R = PL/A => L =
RA/P
=
21 x 4π x 108/1.1 x 10-6
= 2.40
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