Physics
WAEC 1992
A metal of mass 1.5 kg was heated from 27
oC to 47
oC in 4 minutes by a boiling ring of 75 W rating. Calculate the specific heat capacity of the metal, (Neglect heat losses to the surrounding)
-
A.
2.5 X103J kg-10C-1
-
B.
6.0 X102J kg-10C-1
-
C.
2.5 x 102J kg-10C-1
-
D.
1.4 X102J kg-10C-1
-
E.
1.0 x 102J kg-10C-1
Correct Answer: Option B
Explanation
I.Vt = mcθ; C =
I.Vt/mθ
=
75 x 4 x 60/1.5 x 20
= 6.0 X10
2J kg
-10C
-1
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}