Physics
WAEC 1990
A cell of e.m.f. 1.5 V and internal resistance of 2.59 is connected in series with an ammeter of resistance 0.59 and a resistor of resistance 7.09. Calculate the current in the circuit.
-
A.
0.15 A
-
B.
0.20 A
-
C.
0.60A
-
D.
3.00A
-
E.
6.67 A.
Correct Answer: Option A
Explanation
I =
E/R + r
=
1.5/2.5 + 0.5 + 7
= 0.15
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