In the circuit above, three resistors, 2Ω, 4Ω and 12Ω are connected in parallel and a 12V battery is connected across the combination. The current flowing through the 12Ω resistors is
I = \(\frac{V}{R}\) from Ohm's law
I = \(\frac{12}{12}\) = 1A.
There is an explanation video available below.
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