Physics
JAMB 2007
The figure above shows 4 forces 3N, 10N, 3√3N and 6N acting on a particle P. The resultant of he four forces is
-
A.
5N
-
B.
5√ 3N
-
C.
10N
-
D.
10√ 3N
Correct Answer: Option C
Explanation
Resolution of force:
Total vertical upward force:
= 3√3 + 10 cos 60
o
= 3√3 + 5.
Total downward force
= 6 cos 30
o
= 6 x √(
3/
2) = 3√3
Total horizontal forces towards right;
= 3N + cos 30
o
= 3N + 10 x √(
3/
2)
= 3N + 5√3
Total horizontal forces towards left:
= 6 cos 60
o
= 6 x 0.5
= 3.0N
Summary:
Vertical resultant forces upward:
= 3√3 + 5 - 3√3
= 5N
Horizontal resultant forces towards right:
= 3N + 5√3 - 3√3
= 5N
Horizontal resultant force towards right
= 3N + 5√3 - 3N
= 5√3N
∴ R
2 = 5
2 + (5√3)
2
= 25 + 25 x 3
= 100
∴ R = √100
= 10N
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