Correct Answer: Option D

Explanation

The stopping potential is the potential required to stop the most energetic photo-emitted electron. From the relation e Vs = K.E,_(max) where e is the electron charge, and Vs is the stopping potential => e x Vs = 0.34eV
∴ Vs = (0.34eV) / e = 0.34V
∴ stopping potential = 0.34V

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