Evaluate \(\int^{\frac{\pi}{2}} _{\frac{-\pi}{2}} cos x dx\)
\(\int^{\frac{\pi}{2}} _{\frac{-\pi}{2}} cos x dx = [sinx]^{\frac{\pi}{2}} _{\frac{-\pi}{2}}\\ =sin\frac{\pi}{2} - sin\frac{-\pi}{2}\) = sin90 – sin-90 = sin90 – sin270 = 1 – (-1) = 1+1 = 2
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