Correct Answer: Option D

Explanation

\(\int_1 ^2(6x^2-2x)\)dx = \(\frac{6x^3}{3}-\frac{2x^2}{2}]_1 ^2\)
= \(2x^3 - x^2)_1^2\)
= [2(2)3 - (2)2] – [2(1)3 - (1)2]
= [16-4] – [2-1]
= 12 – 1
= 11

There is an explanation video available below.

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