Mathematics
JAMB 2007
Find the locus of point equidistant from two straight lines y - 5 = 0 and y - 3 = 0
-
A.
y - 2 = 0
-
B.
y - 4 = 0
-
C.
y - 1 = 0
-
D.
y - 3 = 0
Correct Answer: Option B
Explanation
Locus of point P equidistant from y - 5 = 0 and y - 3 = 0 is y = 4 i.e y - 4 = 0
There is an explanation video available below.
Report an Error
Ask A Question
Download App
Explanation Video
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}