In the diagram below, AB||DC, the bisectors of < BAC and < ACD meet at E. Find the value of < AEC
∠BAC = 90°
∠ACD = 90° if AE and CE are the bisectors of ∠BAC and ∠ACD respectively ∠BAE = 45°; ∠DCE = 45°
∴ ∠EAC = ∠ECA = 45°
But ∠EAC + ∠ACE + ∠AEC = 180° (angle in a △)
∴ 45° + 45° + ∠AEC = 180°
∠AEC = 180° - 90°
∠AEC = 90°
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