In the diagram above, PQ is parallel to TU, < PQR = 50º, < QRS = 86º, and < STU = 64º. Calculate the value of x
∴ ∠VRS = 94º (angle on a straight line)
∠VTS = 116º (adjacent angle on a straight line)
∠RVT = 50° (corresponding angles)
∴ 94º + 50° + 116° + x = 360° x + 260° = 360°
x = 100°
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