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The diagram above is a circle with centre C. P, Q and S are points...

Mathematics
JAMB 2023


The diagram above is a circle with centre C. P, Q and S are points on the circumference. PS and SR are tangents to the circle. ∠PSR = 36\(^o\). Find ∠PQR

  • A. 72\(^0\)
  • B. 36\(^0\)
  • C. 144\(^0\)
  • D. 54\(^0\)
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Correct Answer: Option A
Explanation

From ∆PSR

|PS| = |SR| (If two tangents are drawn from an external point of the circle, then they are of equal lengths)

∴ ∆PSR is isosceles

∠PSR + ∠SRP + ∠SPR = 180\(^o\) (sum of angles in a triangle)

Since |PS| = |SR|; ∠SRP = ∠SPR

⇒ ∠PSR + ∠SRP + ∠SRP = 180\(^o\)

∠PSR + 2∠SRP = 180\(^o\)

36\(^o\) + 2∠SRP = 180\(^o\)

2∠SRP = 180\(^o\) - 36\(^o\)

2∠SRP = 144\(^o\)

∠SRP = \(\frac {144^o}{2} = 72^0\)

∠SRP = ∠PQR (angle formed by a tangent and chord is equal to the angle in the alternate segment)

∴ ∠PQR = 72\(^0\)

There is an explanation video available below.


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Explanation Video

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WAEC and NECO CBT App for Mobile Devices - Candidates, Schools, Centres, Resellers - 100% Offline -Download Now
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Your School's Whatsapp Group - Join Us now
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC and NECO CBT App for Mobile Devices - Candidates, Schools, Centres, Resellers - 100% Offline -Download Now
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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