Solve for x: 3(x – 1) ≤ 2 (x – 3)
3(x – 1) ≤ 2 (x – 3) = 3x – 3 ≤ 2x – 6 Add 3 to both sides = 3x – 3+ 3 ≤ 2x – 6+ 3 = 3x ≤ 2x – 3 Subtract 2x from both the sides = 3x – 2x ≤ 2x – 3 – 2x ∴ x ≤ -3
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