-
A.
11112
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B.
110112
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C.
101112
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D.
110012
Correct Answer: Option B
Explanation
Convert the binary to base 10 and they convert back to base two
10011
2 + xxxxx
2 + 11100
2 + 101
2 = 1001111
2
(1 × 2
4 + 0 × 2
3 + 1 × 2
2 + 1 × 2
1 + 1 × 2
0) + xxxxx
2 +(1 × 2
4 + 1 × 2
3 + 1 × 2
2 + 0 × 2
1 + 0 × 2
0) + (1 × 2
2 + 0 × 2
1 + 1 × 2
0)
= (16 + 0 + 0 + 2 + 1) + xxxxx
2 + (16 + 8 + 4 + 0 + 0 ) + (4 + 0 + 1)
=(64 + 0 + 0 + 8 + 4 + 2 + 1)
19 + xxxxx
2 + 33 = 79
xxxxx
2 + 52 = 79
xxxxx
2 = 79 − 52
xxxxx
2 = 27
10
\( \begin{array}{c|c}
2 & 27 \\
\hline
2 & 13 \text{ rem 1}\\
2 & 6 \text{ rem 1}\\
2 & 3 \text{ rem 0}\\
2 & 1 \text{ rem 1}\\
& 0 \text{ rem 1}\\
\end{array}\uparrow \)
27
10 = 11011
2
Therefore xxxxx
2 = 27
10 = 11011
2
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