Mathematics
WAEC 2008
In the diagram, < QPR = 60
o
< PQR = 50
o
< QRS = 2x
o
< SRP = 3x
o
< UQP = y
o and RS//TU
calculate y
-
A.
102o
-
B.
78o
-
C.
70o
-
D.
60o
Correct Answer: Option A
Explanation
< RQT = < QRS = 2x (Alternate angles). But in \(\bigtriangleup\) PRQ
50 + 60 + (2x + 3x) = 180
o(Angles in a triangle)
110 + 5x = 180
o
5x = 180
o - 110 = 70
o
x = \(\frac{70}{5}\) = 14
o
Also y + 50 + 2(14) = 180
o
y + 50 + 28 = 180
o
y = 180 - 78
y = 102
o
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