Correct Answer: Option D

Explanation

Area of section = \(\frac{60^o}{360^o}\) x 11r²

= \(\frac{60}{360} \times \pi \times 2^2\)

= \(\frac{1}{6}\) x 4

= \(\frac{4\pi}{6}\)

= \(\frac{2\pi}{3}\)

Area of triangle = \(\frac{1}{2x}\)

= 2 x 28.......60

Segment Area = Area of section - Area of triangle

= \(\frac{2\pi}{3}\) -3

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