Mathematics
JAMB 1979
PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If < PQS = 15
o find < QRS
-
A.
75o
-
B.
37\(\frac{1}{2}\)o
-
C.
127\(\frac{1}{2}\)o
-
D.
105o
Correct Answer: Option D
Explanation
PSO = 90o(angle in a semicircle)
SPO = 180o - (90o + 15o) = 75o
< QRS = 108o - 75o
= 105o(opposite angles in cyclic quadrilateral are supplementary)
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}