Mathematics
JAMB 1980
Solve the equation for the positive values of \(\theta\) less than 360
o. 3 tan \(\theta\) + 2 = -1
-
A.
135o or 315o
-
B.
45o or 135o
-
C.
315o or 180o
-
D.
315v + 45o
-
E.
360o or 315o
Correct Answer: Option A
Explanation
3 tan \(\theta\) + 2 = -1
3 tan \(\theta\) \(\frac{-3}{3}\) = -1
\(\theta\) = tan -1(-1)
\(\theta\) = 360o - 45o
= 315o
\(\theta\) = 180 - 45o = 135o
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