PQR is a triangle in which PQ = 10cm and QPR = 60oS is a...

JAMB 1988

PQR is a triangle in which PQ = 10cm and QPR = 60^oS is a point equidistant from P and Q. Also S is a point equidistant from PQ and PR. If U is the foot of the perpendicular from S on PR, find the length SU in cm to one decimal place

A. 2.7
B. 4.33
C. 3.1
D. 3.3

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Correct Answer: Option B

Explanation

\(\bigtriangleup\)PUS is right angled

\(\frac{US}{5}\) = sin60^o

US = 5 x \(\frac{\sqrt{3}}{2}\)

= 2.5\(\sqrt{3}\)

= 4.33cm

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PQR is a triangle in which PQ = 10cm and QPR = 60oS is a...

Correct Answer: Option B

Explanation

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