Correct Answer: Option A

Explanation

\(\log_{3} p + 3\log_{3} q = 3\)

\(\log_{3} p + \log_{3} q^{3} = 3\)

\(\implies \log_{3} (pq^{3}) = 3\)

\(pq^{3} = 3^{3} = 27\)

\(\therefore p = \frac{27}{q^{3}}\)

= \((\frac{3}{q})^{3}\)

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