Mathematics
JAMB 2012
The distance between the point (4, 3) and the intersection of y = 2x + 4 and y = 7 - x is
-
A.
\(\sqrt{13}\)
-
B.
\(3\sqrt{2}\)
-
C.
\(\sqrt{26}\)
-
D.
\(10\sqrt{5}\)
Correct Answer: Option B
Explanation
P
1 (4, 3), P
2 (x, y)
y = 2x + 4 .....(1)
y = 7 - x .....(2)
Substitute (2) in (1)
7 - x = 2x + 4
7 - 4 = 2x + x
3 = 3x
x = 1
Substitute in eqn (2)
y = 7 - x
y = 7 - 1
y = 6
P
2 (1, 6)
Distance between 2 points is given as
D = \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)
D = \(\sqrt{(1 - 4)^2 + (6 - 3)^2}\)
D = \(\sqrt{(-3)^2 + (3)^2}\)
D = \(\sqrt{9 + 9}\)
D = \(\sqrt{18}\)
D = \(\sqrt{9 \times 2}\)
D = \(3\sqrt{2}\)
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