Mathematics
WAEC 2005
In the diagram, PR is a diameter, ∠PRQ = (3x-8)
o and ∠RPQ = (2y-7)
o. s x in terms of y
-
A.
\(x=\frac{75-2y}{3}\)
-
B.
\(x=\frac{105-3y}{2}\)
-
C.
\(x=\frac{105-2y}{3}\)
-
D.
\(x=\frac{75-3y}{2}\)
Correct Answer: Option C
Explanation
180 = ∠RPQ + ∠PRQ + ∠PQR Since PQR = 90 (theorem: angle in a semi circle)
180 = ∠RPQ + ∠PRQ + 90 => 180o = (3x-8)o+(2y-7)o+90o; 90+8+7 = 3x+2y =>\(\frac{105-2y}{3}=x\)
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}