-
A.
\(\frac{b(a-x+1)}{a+1}\)
-
B.
\(\frac{a+1}{b(a-x+1)}\)
-
C.
\(\frac{a(b-x+1)}{b+1}\)
-
D.
\(\frac{b}{a(b-x+1)}\)
Correct Answer: Option A
Explanation
If \(\frac{bx+y(a+1)}{b(a+1)}=1\\
bx + ya + y = ba + b; y(a+1) = ba+b-bx\\
y(a+1)=b(a+1-x); y = \frac{b(1+a-x}{a+1}\)
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}