Mathematics
WAEC 2001
A man is four times as old as his son. The difference between their ages is 36 years Find the sum of their ages
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A.
45 years
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B.
48 years
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C.
60 years
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D.
74 years
Correct Answer: Option C
Explanation
Let the sons age be x. The father is 4x
∴ 4x - x = 36; 3x = 36; x = 12
The son is 12 years and the father is 12 x 4 = 48.
The sum of their ages (12 + 48) years = 60years
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