In the diagram O is the center of circle PRQ. The radius is 3.5cm and ∠POQ = 50o. Use the diagram to answer question below. (take π = 3.142)
Calculate, correct to three significant figures, the area of sector OPQ
Area of a sector = \(\frac{\theta}{360}\) x \(\pi\)r\(^2\)
Area of a sector = \(\frac{50}{360}\) x 3.142 x 3.5 x 3.5
= \(\frac{50 \times 3.142\times 3.5 \times 3.5}{360}\)
= \(\frac{1924.475}{360}\) ≈ 5.346cm\(^2\)
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