In the parallelogram PQRS, PE is perpendicular to QR. Find the area of the parallelogram.

Mathematics

JAMB 1979

A. 60cm²
B. 65cm²
C. 72cm²
D. 132cm²
E. 156cm²

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Correct Answer: Option D

Explanation

By Pythagoras, PE\(^2\) = 12\(^2\) - 5\(^2\)

= 144 - 25 = 119

h = PE\(^2\) = √119 = 10.9 ≈ 11cm,

Area of 11gm = b x h

QR = b =(5 + 7)cm = 12cm

area = 12 x 11

= 132cm\(^2\)

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In the parallelogram PQRS, PE is perpendicular to QR. Find the area of the parallelogram.

Correct Answer: Option D

Explanation

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