Mathematics
WAEC 1995
In the diagram above, AB//CD, the bisector of ∠BAC and ∠ACD meet at E. Find the value of ∠AEC
-
A.
30o
-
B.
45o
-
C.
60o
-
D.
75o
-
E.
90o
Correct Answer: Option E
Explanation
Ae is a bisector of BAC => EAC = 45
o
CE is the bisector of ACD => ACE = 45
o
AEC = 180
o - [EAC + ACE]
    = 180
o - (45
o + 45
o) = 180
o - 90
o = 90
o
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}