Mathematics
WAEC 1988
What is the probability of having an odd number in a single toss of a fair die?
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A.
1/6
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B.
1/3
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C.
1/2
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D.
2/3
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E.
5/6
Correct Answer: Option C
Explanation
n(S) = 6(odd) = {1, 3, 5}
n(odd) = 3
pr(odd) = \(\frac{n(odd)}{n(S)}\) 3/6 =1/2
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