Find the coordinate of the point on the curve y = x\(^2\) + 4x - 2, where the gradient is zero
Equation of a curve : y = x\(^2\) + 4x - 2
the gradient of a curve , m = \(\frac{\text{dy}}{\text{dx}}\)
\(\frac{\text{dy}}{\text{dx}}\) = 2x + 4
But m = 0
2x + 4 = 0
x = -\(\frac{4}{2}\)
x = -2
Hence, the x coordinate is -2.
Substitute x = -2 into y = f(-2) to determine y: y = (-2)\(^2\) + 4(-2) - 2
y = 4 - 8 - 2 = -6
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