A force of 32 newtons is applied to an object of mass m kg, which is at rest on a smooth horizontal surface. if acceleration produced is 8ms\(^{-2}\), find the value of m
Force, f = 32
Acceleration, a = 8ms\(^{-2}\)
mass, m = mkg
From Newton's second law of motion, F = Ma
32 = 8m
m = \(\frac{32}{8}\) = 4kg.
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