\(Simplify: \frac{log √27 - log √8}{log 3 - log 2}\)
\(\frac{log √27 - log √8}{log 3 - log 2}\)
= \(\frac{log √3^3 - log √2^3}{log 3 - log 2}\)
= \(\frac{log3^{3/2} - log2^{3/2}}{log3}\)
=\(\frac{^3/_2(log 3 - log 2)}{log 3 - log 2}\)
\(\therefore\frac{3}{2}\)
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