Add 127\(_{16}\) to 50A\(_{16}\)
a
629\(_{16}\)
b
630\(_{16}\)
c
631\(_{16}\)
d
632\(_{16}\)
Explanation
Correct Option
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Onota
1 year ago
Briefly: In hexadecimal (base-16), 'A' represents the decimal value 10. SO Briefly: Convert to decimal: 127
16
=1×16
2
+2×16
1
+7×16
0
=256+32+7=295
10
. 50A
16
=5×16
2
+0×16
1
+10×16
0
=1280+0+10=1290
10
. Add in decimal: 295+1290=1585
10
. Convert back to hexadecimal: 1585÷16=99 remainder 1 (1
16
), 99÷16=6 remainder 3 (3
16
), 6÷16=0 remainder 6 (6
16
). So, 631
16
.
