Correct Answer: Option B

Explanation

1 Faraday of electricity is equal to the charge of 1 mole of electrons, which is 96,485 coulombs. The reduction of copper(II) ions in solution to copper metal requires 2 electrons per ion, so 1 Faraday of electricity will deposit 0.5 moles of copper.
1 Faraday * (2 electrons/Cu ion) / (1 mole electrons/96,485 coulombs) * (1 mole Cu/2 electrons) = 0.5 moles Cu

• how many grams of Hydrogen gas will be produced when 6 grams of magnesium ribbon dissolves in 500cm³ of 6M... Answer this

  2 Answers   ·   Chemistry   ·   3 weeks ago
• Itemise and explain six problem of distribution of commodities in West Africa? Answer this

  1 Answers   ·   3 hours ago
• If 1 litre of 2.2M sulphuric acid is poured into a bucket containing 10 litres of water, and the resulting... Answer this

  1 Answers   ·   Chemistry   ·   3 weeks ago