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Determine the volume of 0.100 mol of HCl in \(0.250 mol dm^3\) of solution.

Chemistry
WAEC 2023

Determine the volume of 0.100 mol of HCl in \(0.250 mol dm^3\) of solution.

  • A. \(200cm^3\)
  • B. \(100cm^3\)
  • C. \(20cm^3\)
  • D. \(400cm^3\)
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Correct Answer: Option D
Explanation

Molarity = 0.100 mol / 0.250 mol dm3
= 0.100 mol / 0.250 dm3 * 1000 cm3/dm3
= 400 cm3
Volume (V) = Amount (n) / Concentration (C)
Given that the amount of HCl is 0.100 mol and the concentration of the solution is 0.250 mol/dm³, you can calculate the volume:
Volume (V) = 0.100 mol / 0.250 mol/dm³ = 0.4 dm³
Since 1 dm³ is equal to 1000 cm³, you can convert the volume from dm³ to cm³:
Volume (V) = 0.4 dm³ × 1000 cm³/dm³ = 400 cm³
Therefore, the volume of 0.100 mol of HCl in a 0.250 mol/dm³ solution is 400 cm³.


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WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts