Chemistry
WAEC 2015
A compound has an empirical formular CH
2O and molecular mass of 90.
[H = 1.00, C = 12.0, O = 16.0]
-
A.
C4H10O2
-
B.
C3H10O2
-
C.
C3H6O3
-
D.
C2H2O4
Correct Answer: Option C
Explanation
(CH2O)n = 90; (12 + (1 x 2) + 16)n = 90
(12 + 2 + 16)n = 90; 30n = 90; n = \(\frac{90}{30}\); n = 3
(CH2O)3 = Molecular formula ; = C3H6O3
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