Chemistry
WAEC 2016
The mass of potassium hydroxide required to make 300.ocm
3 of 0.4 moldm
-3 solution is {KOH = 56.0}
-
A.
26.88g
-
B.
13.44g
-
C.
6.72g
-
D.
3.36g
Correct Answer: Option C
Explanation
300cm3 of 0.4moldm3
1000cm3 contains 0.4mole
300cm3 will contain \(\frac{300 \times 0.4}{1000}\)
= 0.12mole
Number of moles = \(\frac{Mass}{\text {Molecular mass}}\)
Mass = number of moles x m.mass
= 0.12 x 56 = 6.72g
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