Correct Answer: Option C

Explanation

2NaHCO_3(s) \(\rightarrow\) 2Na₂CO _3(S) + CO _2(g) + H₂O_(g)

2 moles of 2NaHCO_3(s) produces 22.4dm³ of CO₂

0.5 moles of 2NaHCO₃ will produce \(\frac{0.5 \times 22.4}{2}\)

= \(\frac{11.2}{2}\)

= 5.6 dm³

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