Correct Answer: Option B

Explanation

From Faraday;s second law of electrolysis

\(\frac{\text{Mass of silver deposited}}{\text{Mass of copper deposited}}\) = \(\frac{\text{Equivalent mass of silver}}{\text{Equivalent mass of copper}}\)

\(\frac{\text{Mass of silver deposited}}{1.0g}\) = \(\frac{108}{63.5}\)

= 31.75g

Copper is devalent = Cu²⁺

Mass of silver deposited = \(\frac{108g}{31.75g}\)

= 3.30g

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