Chemistry
JAMB 2003
What mass of K
2CrO
4 is required to prepare 250cm
3 of 0.020 mol dm
3 solution?
[K
2CrO
4 = 194.2g mol
-1]
-
A.
0.97g
-
B.
9.70g
-
C.
19.42g
-
D.
97.10g
Correct Answer: Option A
Explanation
1 mole m
-3 K
2CrO
4 contains 194.2g mol
-1 in 1000cm
3
1 mole m
-3 K
2CrO
4 contains 92.2g mol
-1 in 500cm
3
1 mole m
-3 K
2CrO
4 contains 48.55g mol
-1 in 250cm
3
If n molm
-3 K
2CrO
4 contain 48.55
0.02 molm
-3 will contain (0.02/1) * (48.55/1) = 0.97g
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