Chemistry
JAMB 1997
How many Faraday of electricity are required to deposit 0.20 mole of nickel, if 0.10 Faraday of electricity deposited 2.98g of nickel during electrolysis of its aqueous solution?
(Ni = 58.7, 1F = 96 500 C mol
-)
-
A.
0.20
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B.
0.30
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C.
0.40
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D.
0.50
Correct Answer: Option C
Explanation
No of mole → (2.98)/(58.7) ..............0.1
2.0 .................x
∴ x = (0.2)/(2.98) x 58.7 x 0.40
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