if y=x sinx,find dy/dx when x=^2?

Pdav80119

4 months ago

y = x sinx
dy/dx = x•cosx + sinx•1
= xcosx + sinx

At x = π/2:
= (π/2)cos(π/2) + sin(π/2)
= (π/2)•0 + 1
= 1