Two fair dice are thrown, what is the probability of getting 1. The sun of 9 2. Two odd numbers 3. Two prime numbers 4. Two factors of 12?

DarkBlade1Z3

1 year ago

1. To get a sum of 9, it can be (3,6), (6,3) (4,5) (5,4) to get both 3 and 6 it will be 1/6*1/6 = 1/36, since there is two chances 1/36+ 1/36 +1/36+1/36= 4/36= 1/9.
(b) Two odd numbers:

We count the number of ways to get two odd numbers: (1,3), (1,5), (1,7), (3,1), (3,5), (3,7), (5,1), (5,3), and (5,7).

possible outcomes = 9,

So, the total possible outcomes = 6x6=36 = 9/36 = 1/4.

(c) Two prime numbers

We estimate the number of ways we can get two prime numbers: (2,3), (3,2), (5,2), and (2,5)

possible outcomes = 4,

So, the total possible outcomes = 6x6 =36 = 4/36, = 1/9.

(d) Two factors of 12:

We count the number of ways and divide by the total possible outcomes.

The factors of 12 are 1, 2, 3, 4, 6, and 12: (2,6), (3,4), and (4,3) = 3 ways

possible outcomes = 6

Therefore, the total number of possible outcomes = 6x6=36 = 3/36, = 1/12\
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MR2

1 year ago

1 1/8
2 1/4
3 1/4
4 23/36