when titanium chloride was electrolysed by passing 0.12.A current through the solution for 500 seconds,0.015g of titanium was deposited. what is the charge on the titanium ion? (IF=96500 C,Ti=48.0)?

LawsonOche

1 year ago

Given data:

Current (I) = 0.12 A

Time (t) = 500 seconds

Mass of titanium deposited (m) = 0.015 g

Faraday's constant (F) = 96500 C

Molar mass of titanium = 48.0 g per mol


Steps to find the charge on the titanium ion:

1. Calculate the total charge (Q):

Q = I multiplied by t

Q = 0.12 A multiplied by 500 seconds

Q = 60 C



2. Calculate the number of moles of titanium deposited:

Number of moles = mass divided by molar mass

Number of moles = 0.015 g divided by 48.0 g per mol

Number of moles = 0.0003125 mol



3. Calculate the charge required to deposit the titanium:

Charge (Q) = Number of moles multiplied by Faraday's constant

Charge = 0.0003125 mol multiplied by 96500 C per mol

Charge = 30.15625 C



4. Determine the number of moles of titanium ions deposited:

Set the total charge equal to the product of the number of moles, charge on the titanium ion (z), and Faraday's constant:

60 C = Number of moles multiplied by z multiplied by Faraday's constant



5. Solve for z:

z = 60 C divided by (0.0003125 mol multiplied by 96500 C per mol)

z = 60 divided by 30.15625

z = 1.987, which is approximately 2




:

The charge on the titanium ion is approximately 2.