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(a) Expand (2 x)^5(1-2x)^6as 5 the term in x'. far as 20 (b) By putting...

(a) Expand (2 x)^5(1-2x)^6as 5 the term in x'. far as 20 (b) By putting x = -0.001 in your result in (a) above, evaluate: (1.999). (1.002) correct to 5 decimal places.?
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