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an electric heater of 200ohms makes use of an alternating current of peak voltage 3.5 ampere.Determine the power dissipated?

2august2008

1 Nov, 2023

Atiku Abubakar College of Legal and Islamic Studies

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2 years ago

R=200 ohms
I=3.5A

P=I²R

P= 3.5²x 200

P=12.25 x 200

P= 2,450W
Therefore, the power dissipated is 2,450W

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