A lorry starts from rest and accelerates uniformly until it reaches a velocity of 50m/s after 10secs. it travels with uniform velocity of 5seconds and it brought to rest 15secs with uniform retardation. determine: a.)sketch the motion graphically b.) calculate the acceleration of the lorry c. calculate the retardation d. total distance traveled e. the average speed?

Tifepraise

2 years ago

b.) To calculate the acceleration of the lorry, we can use the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the values, we have: acceleration = (50 m/s - 0 m/s) / 10 s = 5 m/s².

c.) To calculate the retardation, we can use the same formula as acceleration. The final velocity is 0 m/s, the initial velocity is 50 m/s, and the time is 15 s. Plugging in the values, we have: retardation = (0 m/s - 50 m/s) / 15 s = -3.33 m/s².

d.) To calculate the total distance traveled, we can use the formula: distance = (initial velocity * time) + (0.5 * acceleration * time^2).

For the first phase, the initial velocity is 0 m/s, the time is 10 s, and the acceleration is 5 m/s². Plugging in the values, we have: distance = (0 m/s * 10 s) + (0.5 * 5 m/s² * (10 s)^2) = 250 m.

For the second phase, the velocity is constant at 50 m/s for 5 seconds, so the distance is: distance = 50 m/s * 5 s = 250 m.

For the third phase, the initial velocity is 50 m/s, the time is 15 s, and the retardation is -3.33 m/s². Plugging in the values, we have: distance = (50 m/s * 15 s) + (0.5 * -3.33 m/s² * (15 s)^2) = 375 m.

The total distance traveled is the sum of the distances from each phase: 250 m + 250 m + 375 m = 875 m.