How to prepare 0.2N solution of Ca(OH)2 with a volume of 250ml. What weight of solute required?
oladipuposaheed
13 Jul, 2023
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To prepare a 0.2N solution of Ca(OH)2 with a volume of 250 ml, you'll need to determine the molecular weight of Ca(OH)2 and then calculate the weight of the solute required.
The molecular weight of Ca(OH)2 can be calculated as follows:
Ca(OH)2 = (1 * atomic mass of Ca) + (2 * atomic mass of O) + (2 * atomic mass of H)
Using the periodic table, we find that the atomic mass of Ca is 40.08 g/mol, the atomic mass of O is 16.00 g/mol, and the atomic mass of H is 1.01 g/mol.
Therefore:
Molecular weight of Ca(OH)2 = (1 * 40.08) + (2 * 16.00) + (2 * 1.01)
= 40.08 + 32.00 + 2.02
= 74.10 g/mol
Now, let's calculate the weight of the solute required for a 0.2N solution with a volume of 250 ml:
Weight of solute (in grams) = (N * molecular weight * volume) / 1000
Where:
N = normality of the solution
Molecular weight = molecular weight of Ca(OH)2
Volume = volume of the solution in liters
Plugging in the values:
Weight of solute = (0.2 * 74.10 * 0.250) / 1000
= 3.705 g
Therefore, you would need approximately 3.705 grams of Ca(OH)2 to prepare a 0.2N solution with a volume of 250 ml.